Step 1: Write the unbalanced chemical equation.
Al + O2 → Al2O3
Step 2: Make a list of the number of atoms of each element on reactant and
product
side.
Step 3: Pick an element and find out its least common multiple (LCM). Let us
pick
oxygen. LCM for 2 and 3 is 6.
Step 4: Divide the LCM with the number of atoms of that element and put the
result
as the coefficient on opposite sides.
Step 4a: There are 2 oxygen atoms on the reactant side; 6 divided by 2 is 3, so
put 3 as the coefficient of oxygen on the reactant side.
Al + 3O2 → Al2O3
Step 4b: There are 3 oxygen atoms on the product side; 6 divided by 3 is 2, so
put
2 as the coefficient of oxygen on the reactant side.
Al + 3O2 → 2Al2O3
Oxygen is balanced!
Step 5: Repeat Step 3 and 4 for aluminium.
4Al + 3O2 → 2Al2O3
Step 6: Balanced chemical equation.
Both reactant and product sides have equal number of atoms for each element. The
chemical
equation is now balanced!
| Reactants | Products |
|---|---|
| Al = 1 | Al = 2 |
| O = 2 | O = 3 |
| Reactants | Products |
|---|---|
| Al = 1 | Al = 2 |
| O = 2 × 3 = 6 | O = 3 |
| Reactants | Products |
|---|---|
| Al = 1 | Al = 2 × 2 = 4 |
| O = 2 × 3 = 6 | O = 2 × 2 = 6 |
| Reactants | Products |
|---|---|
| Al = 1 × 4 = 4 | Al = 4 |
| O = 6 | O = 6 |
| 2 | 2, 3 |
| 3 | 1, 3 |
| 1, 1 |
Tap on the button to fill up the table and then use the + and - buttons to change the coefficients of the elements to balance the chemical reaction.
| Table for number of atoms | ||
|---|---|---|
| Elements | Reactants | Products |
\(\text{Fe}_2\text{O}_3~+\) \(\text{C} \rightarrow\) \(\text{Fe}~+\) \(\text{CO}_2\)
Identify the value of x : y, if the given chemical equation is
balanced.
\(~~~~~~~~~~~~~~~~~~~~\text{xFe}~+~\text{yCl}_2 \rightarrow \text{2FeCl}_3\)
Solution
| Reactants | Elements | Products |
|---|---|---|
| 2 | Fe | 2 |
| 6 | Cl | 6 |
The balanced chemical equation for the reaction of iron with chlorine is:
\(~~~~~~~~~~~~\text{2Fe}~+~\text{3Cl}_2 \rightarrow \text{2FeCl}_3\)
\(~~~~~~\) Thus, the value of x : y is 2 : 3.